Y =
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\space X \neq a
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Simplify the following expression and state the condition under which the simplification is valid.
You can assume that X \neq 0.
Y = \dfrac{NUMERATOR}{DENOMINATOR}
Y =
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\space X \neq a
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x + 2First factor out the greatest common factors in the numerator and in the denominator.
\qquad Y = \dfrac
{NUM_FACTOR(NUMERATOR.divide(NUM_FACTOR))}
{DEN_FACTOR(DENOMINATOR.divide(DEN_FACTOR))}
\qquad Y =
-\dfrac{NUM_FACTORa}{DEN_FACTORa} \cdot
\dfrac{NUMERATOR.divide(NUM_FACTOR)}{DENOMINATOR.divide(DEN_FACTOR)}
Simplify:
\qquad Y = -
\dfrac{NUM_FACTOR2}{DEN_FACTOR2} \cdot
NUM_FACTOR2 \cdot
\dfrac{NUMERATOR.divide(NUM_FACTOR)}{DENOMINATOR.divide(DEN_FACTOR)}
Next factor the numerator and denominator.
\qquad Y = -
\dfrac{NUM_FACTOR2}{DEN_FACTOR2} \cdot
NUM_FACTOR2 \cdot
\dfrac{(FACTOR)(TERM1)}{(FACTOR)(TERM3)}
Assuming X \neq -A, we can cancel the FACTOR.
\qquad Y = -
\dfrac{NUM_FACTOR2}{DEN_FACTOR2} \cdot
NUM_FACTOR2 \cdot
\dfrac{TERM1}{TERM3}
Therefore:
\qquad Y = \dfrac{
TERM1.multiply(-1)
TERM1
-NUM_FACTOR2(TERM1)}{
TERM3
DEN_FACTOR2(TERM3)},
X \neq -A