Y = \space a
\space X \neq \space a
Simplify the following expression and state the condition under which the simplification is valid.
Y = \dfrac{X^2 + CONSTANT}{X + A}
Y = \space a
\space X \neq \space a
x + 2
The numerator is in the form \pink{a^2} - \blue{b^2},
which is a difference of two squares so we can factor it as
(\pink{a} + \blue{b})(\pink{a} - \blue{b}).
\qquad a = X
\qquad b = \sqrt{A * A} = A
So we can rewrite the expression as:
Y =
\dfrac{(\blue{X} + \pink{A})(\blue{X} \pink{-A})}
\dfrac{(\blue{X} \pink{A})(\blue{X} + \pink{-A})}
{X + A}
We can divide the numerator and denominator by (X + A)
on condition that X \neq -A.
Therefore
Y = X + -A; X \neq -A
Simplify the following expression:
Y =
\dfrac{X^2 + plus(LINEAR + X) + CONSTANT}{X + -A}
Y = \space a
\space X \neq \space a
x + 2
X^2 + plus(LINEAR + X) + CONSTANT = (X + -A)(X + -B)
So we can rewrite the expression as:
Y =
\dfrac{(X + -A)(X + -B)}{X + -A}
We can divide the numerator and denominator by (X + -A)
on condition that X \neq A.
Therefore
Y = X + -B; X \neq A
First factor the polynomial in the numerator.