Fill in the blank.
WHOLE\ fraction( M_NUM, M_DENOM, false, true )
____fraction( I_NUM, I_DENOM, false, true )
SOLUTION
<>=First, let's convert the mixed number to an improper fraction with the same denominator.
To get the numerator of the improper fraction, multiply the denominator (M_DENOM_REDUCED) by the whole number (WHOLE) and add the numerator (M_NUM_REDUCED).
M_DENOM_REDUCED \cdot WHOLE+M_NUM_REDUCED = M_AS_I
We can write the mixed number as an improper fraction with numerator M_AS_I and denominator M_DENOM_REDUCED.
Now we need to compare fraction ( M_AS_I, M_DENOM_REDUCED, false, true ) to fraction ( I_NUM, I_DENOM, false, true ).
It is easier to compare these two fractions when they have the same denominator.
Their smallest common denominator is the LCM of M_DENOM_REDUCED and I_DENOM.
\lcm(M_DENOM_REDUCED, I_DENOM) = LCM
The first fraction remains as \dfrac{M_AS_I * F1}{LCM}.
The first fraction becomes \dfrac{M_AS_I * F1}{LCM}.
The second fraction remains as \dfrac{I_NUM * F2}{LCM}.
The second fraction becomes \dfrac{I_NUM * F2}{LCM}.
We see that \dfrac{M_AS_I * F1}{LCM} SOLUTION \dfrac{I_NUM * F2}{LCM}.
Fill in the blank.
WHOLE\ fraction( M_NUM, M_DENOM, false, true )
____fraction( I_NUM, I_DENOM, false, true )
SOLUTION
<>=First, let's convert the mixed number to an improper fraction with the same denominator.
To get the numerator of the improper fraction, multiply the denominator (M_DENOM_REDUCED) by the whole number (WHOLE) and add the numerator (M_NUM_REDUCED).
M_DENOM_REDUCED\cdotWHOLE+M_NUM_REDUCED = M_AS_I
We can write the mixed number as an improper fraction with numerator M_AS_I and denominator M_DENOM_REDUCED.
Now we need to compare fraction ( M_AS_I, M_DENOM_REDUCED, false, true ) to fraction ( I_NUM, I_DENOM, false, true ).
It is easier to compare these two fractions when they have the same denominator.
Their smallest common denominator is the LCM of M_DENOM_REDUCED and I_DENOM.
\lcm(M_DENOM_REDUCED, I_DENOM) = LCM
The first fraction remains as \dfrac{M_AS_I * F1}{LCM}.
The first fraction becomes \dfrac{M_AS_I * F1}{LCM}.
The second fraction remains as \dfrac{I_NUM * F2}{LCM}.
The second fraction becomes \dfrac{I_NUM * F2}{LCM}.
We see that \dfrac{M_AS_I * F1}{LCM} SOLUTION \dfrac{I_NUM * F2}{LCM}.